APSC CSAT Paper Notes Archives

APSC Prelim 2022 CSAT Paper (GS-2) – General Mental Ability sections Questions Analysis

Posted on February 11, 2024March 27, 2024 by admin

APSC Prelim 2022 CSAT Paper (GS-2) – General Mental Ability sections Questions Analysis

Questions from General Mental Ability sections

Go to APSC CCE Prelim Previous Years Paper Analysis

Qs order as per Set – D

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Q26. In the figure below, one space is vacant, which has been indicated as ? :

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Q27. Histogram below shows the production per year in thousand units from 2010 to 2020 for a certain company :

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A person studied the histogram and concluded the following .

(i) The company achieved the highest growth in production per year in 2016 for the decade 2011-2020.

(ii) The production per year shows a negative growth in the year 2019 for the decade 2011-2020.

Now, choose the correct one from the following alternatives.

(A) Both conclusions (i) and (ii) are correct

(B) Only conclusion (i) is correct

(D) Neither conclusion (i) nor conclusion (ii) is correct

Q28. pie diagram below shows the average monthly expenditure of a family. The monthly income of the family is Rs. 50,000.

Consider the following statements

(i) The average monthly expenditure of the family for conveyance is about 10,000.

(ii) The average monthly expenditure of the family for food is about 17,500.

Now, choose the correct one from the following alternatives.

(A) Both conclusions (i) and (ii) are correct

(B) Only conclusion (i) is correct

(D) Neither conclusion (i) nor conclusion (ii) is correct

Q29. graphs below show the production and sales figures of a company for the decade 2011-2020. The company could sell 2 80% Of its products every year during the decade:

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One may conclude the following :

(i) The company effected a price drop in the year 2015.

(ii) Sales-wise, the worst performing year for the company was 2020.

Now, choose the correct one from the following alternatives.

(A) Both conclusions (i) and (ii) are correct

(B) Only conclusion (i) is correct

(D) Neither conclusion (i) nor conclusion (ii) is correct

Q35. Pick up the most appropriate word to fill in the blank from the given alternatives :

float, hook, line, bait, net,

(A) saw

(B) spade

(D) pond

Q36. Pick up the most appropriate word to fill in the blank from the given alternatives .

Bengal, Indo-Chinese, South China, Amur,

(A) Sumatran

(B) Caspian

(D) Javan

Q37. In the given list below, identify the word which is different from the rest :

inflexible, stubborn, obstinate, acquiescent, rigid, dogged

(A) acquiescent

(B) obstinate

(D) rigid

Q38. If Cycle pairs with Velodrome, then Boxing will pair with

(A) Arena

(B) Ring

(D) Pitch

Q50. How many triangles can be formed within a regular octagon, where vertices of the octagon are vertices of the triangles, and each triangle can have only one side common with that of the octagon, but none of the sides passes through the centre of the octagon?

(A) 32

(B) 16

(D) 64

Q51. If the square represents traders, circle represents football lovers and triangle represents women who love football, then which slice represents women who love football, but are not traders?

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(A) C

(B) E

(D) There is no such slice

Q52. If Bus is related to Car, then in the same way, River would be related to

(A) Stream

(B) Pond

(D) Swimming pool

Q61. A and B start walking in opposite directions. A covers 3 km and B covers 4 km. Then A turns right and walks 4 km while B turns left and walks 3 km. How far is each from the starting point?

(A) 5 km

(B) 4 km

(D) 8 km

Q62. In a row of 40 students, Saurav is 24th from the left end and Sachin is *6th from the right end. How many students are there between Saurav and Sachin?

(A) 10

(B) 9

(D) None of the above

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APSC Prelim 2022 GS Paper 1 – Fully solved Answer Key & Detailed Solutions

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Geometry and Mensuration Formulas & Properties – APSC PrelimCSAT Paper Notes, formulas

Posted on November 21, 2020March 18, 2023 by admin

Geometry and Mensuration Important Formulas

& Properties –

Numerical Aptitude Notes for APSC Prelims CSAT Paper, SSC and Competitive Exams

Go to Aptitude, Reasoning and Quants Formulas & Notes

Circle

Area of a circle = R², where R is the radius.
Circumference of a circle = 2πR.
Length of an arc = 2 π r × (θ/360°), where θ is the central angle.
Area of a sector = θ/2 × r².
Perimeter of a semi-circle =πR + 2R.

Quadrilaterals

Parallelogram

Area of parallelogram = (Base x Height).
The diagonals of a parallelogram bisect each other.
Each diagonal of a parallelogram divides it into triangles of the same area.
A parallelogram and a rectangle on the same base and between the same parallels are equal in area.
Of all the parallelogram of given sides, the parallelogram which is a rectangle has the greatest area.

Rectangle

Area of a rectangle = (Length x Breadth).
Perimeter of a rectangle = 2(Length + Breadth).
The diagonals of a rectangle are equal and bisect each other.

Square

Area of a square = (side)² = (diagonal)².
Area of 4 walls of a room = 2 (Length + Breadth) x Height.
The diagonals of a square are equal and bisect each other at right angles.

Rhombus

Area of a rhombus = x (Product of diagonals).
The diagonals of a rhombus are unequal and bisect each other at right angles.

Trapezium

Area of a trapezium = (sum of parallel sides)/2 x distance between them.

Triangle

Sum of the angles of a triangle is 180°.
The sum of any two sides of a triangle is greater than the third side.
Area of a triangle = x Base x Height.
Area of a triangle = s(s-a)(s-b)(s-c), where a, b, c are the sides of the triangle and s = (a + b + c).
Area of an equilateral triangle = sqrt(3)/4 x (side)².

Pythagoras Theorem

In a right-angled triangle, (Hypotenuse)² = (Base)² + (Height)².

Median – The line joining the mid-point of a side of a triangle to the opposite vertex is called the median.
Centroid – The point where the three medians of a triangle meet. The centroid divided each of the medians in the ratio 2 : 1.
In an isosceles triangle, the altitude from the vertex bisects the base.
The median of a triangle divides it into two triangles of the same area.
The area of the triangle formed by joining the mid-points of the sides of a given triangle is one-fourth of the area of the given triangle.

Probability – Important Formulas – APSC Prelim CSAT Paper Notes

Posted on November 21, 2020March 18, 2023 by admin

Probability – Important Formulas & Notes

Numerical Aptitude Notes for APSC Prelims CSAT Paper, SSC and Competitive Exams

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Probability

A quantitative measure of the chance of occurrence of a particular event. The likelihood of the occurrence of a particular event. The probability of event A is often written as P(A).

The probability of an event can only be between 0 and 1 and can also be written as a percentage.

Probability of Occurrence of an Event

Let S be the sample and let E be an event.

P(E) = n(E) /n(S)

Results on Probability

P(S) = 1

0 <= P (E) <= 1

P() = 0

For any events A and B, P(A B) = P(A) + P(B) – P(A B)

Experiment – An operation which can produce some well-defined outcomes is called an experiment.

Random Experiment – An experiment in which all possible outcomes are know and the exact output cannot be predicted in advance, is called a random experiment. Like drawing a card from a pack of well-shuffled cards.

Sample Space – When we perform an experiment, then the set S of all possible outcomes is called the sample space.

In tossing a coin, S = {H, T}

If two coins are tossed, S = {HH, HT, TH, TT}.

In rolling a dice, S = {1, 2, 3, 4, 5, 6}.

Event – Any subset of a sample space is called an event.

Equally Likely Events – Events are said to be equally likely if there is no preference for a particular event over the other.

Mutually Exclusive Events – Two or more than two events are mutually exclusive if the occurrence of one of the events excludes the occurrence of the other.

Independent Events – If the occurrence or non-occurrence of one event does not influence the occurrence or non-occurrence of the other.

Simple Events – Events where one experiment happens at a time and it has a single outcome.

Compound Event – An event in which there is more than one possible outcome.

Exhaustive Events – The mutually exclusive events that form the sample space collectively are called the exhaustive events. Example, when a coin is tossed, either Head or Tail appears and they collectively form the sample space.

L.C.M and H.C.F based Questions – Important Formulas for APSC Prelim CSAT Paper

Posted on November 21, 2020March 18, 2023 by admin

L.C.M and H.C.F based Questions – Important Formulas

Numerical Aptitude Notes for APSC Prelim CSAT Paper, SSC and Competitive Exams

Go to Aptitude, Reasoning and Quants Formulas & Notes

Factors and Multiples:

If number a divided another number b exactly, we say that a is a factor of b.

b is also a multiple of a.

Highest Common Factor (H.C.F.) or Greatest Common Divisor (G.C.D.)

The H.C.F. of two or more than two numbers is the greatest number that divides each of them exactly.

Two methods of finding the H.C.F. of a given set of numbers:

Factorization Method: Express the each one of the given numbers as the product of prime factors. The product of least powers of common prime factors gives H.C.F.

Division Method: To find the H.C.F. of two given numbers, divide the larger by the smaller one. Now, divide the divisor by the remainder. Repeat the process of dividing the preceding number by the remainder last obtained till zero is obtained as remainder. The last divisor is the H.C.F.

Least Common Multiple (L.C.M.)

The least number which is exactly divisible by each one of the given numbers is called their L.C.M.

There are two methods of finding the L.C.M. of a given set of numbers:

Factorization Method Resolve each one of the given numbers into a product of prime factors. Then, L.C.M. is the product of highest powers of all the factors.

Division Method: Arrange the given numbers in a rwo in any order. Divide by a number which divided exactly at least two of the given numbers and carry forward the numbers which are not divisible. Repeat the above process till no two of the numbers are divisible by the same number except 1. The product of the divisors and the undivided numbers is the required L.C.M. of the given numbers.

H.C.F. and L.C.M. of Fractions

H.C.F. = (H.C.F. of Numerators)/(L.C.M. of Denominators)

L.C.M. = (L.C.M. of Numerators)/(H.C.F. of Denominators)

Product of two numbers = Product of their H.C.F. and L.C.M.

Co-primes: Two numbers are said to be co-primes if their H.C.F. is 1.

Comparison of Fraction numbers

Find the L.C.M. of the denominators of the given fractions.
Convert each of the fractions into an equivalent fraction with L.C.M as the denominator, by multiplying both the numerator and denominator by the same number.
The resultant fraction with the greatest numerator is the greatest.

Downstream/Upstream Boat Speed – Important Formulas – APSC PrelimCSAT Paper Notes

Posted on November 21, 2020March 18, 2023 by admin

Downstream/Upstream Boat Speed – Important Formulas

Numerical Aptitude Notes for APSC Prelim CSAT Paper, SSC and Competitive Exams

Go to Aptitude, Reasoning and Quants Formulas & Notes

Still Water: If the speed of the water is zero, i.e. water is stationary, then it is called still water.

Stream: The moving water in the river is known as a stream.

Upstream: If a boat or a swimmer moves in the opposite direction of the stream, then it is called upstream, i.e. direction against the stream.
Downstream: If a boar or a swimmer moves in the same direction of the stream, then it is called downstream, i.e. direction along the stream

If the speed of a boat in still water is u km/hr and Speed of the stream is v km/hr,

Speed downstream = (u + v) km/hr.
Speed upstream = (u – v) km/hr.

If the speed downstream is a km/hr and the speed upstream is b km/hr, then

Boat Speed in still water = ½ (Downstream Speed + Upstream Speed) = 1/2 x (a + b) km/hr.
Rate of stream = ½ (Downstream Speed – Upstream Speed) = 1/2 x (a – b) km/hr.
Average Speed of Boat = {(Upstream Speed × Downstream Speed) / Boat’s Speed in Still Water}

If it takes “T” hours for a boat to reach a point in still water and comes back to the same point then,
the distance between the two points = {(u²-v²) × T} / 2u,
where “u” is the speed of the boat in still water and “v” is the speed of the stream.

If it takes “T” hours more to go to a point in upstream than downstream for the same distance, then
the distance = {(u2-v2) × t} / 2v,
where “u” is the speed of the boat in still water and “v” is the speed of the stream.

If a boat travels a distance downstream in “t1” hours and returns the same distance upstream in “t2” hours, then,
the speed of the man in still water = [v × {(t2+t1) / (t2-t1)}] km/hr,
where “v” is the speed of the stream

Calendar, Odd days, Leap years – Important Formulas – APSC Prelim CSAT Paper Notes, Qs, Formulas

Posted on November 21, 2020March 18, 2023 by admin

Calendar, Odd days, Leap years – Important Formulas & Notes

Numerical Aptitude Notes for APSC Prelims CSAT Paper, SSC and Competitive Exams

Go to Aptitude, Reasoning and Quants Formulas & Notes

Odd Days

To find the day of the week on a given date, use the concept of ‘odd days’.

Number of days more than the complete weeks are called odd days in a given period.

Finding No. of odd Days

1 ordinary year = 365 days = (52 weeks + 1 day.) i.e. 1 ordinary year has 1 odd day.

1 leap year = 366 days = (52 weeks + 2 days) i.e. 1 leap year has 2 odd days.

1 Century = 100 years = 76 ordinary years + 24 leap years = (76 x 1 + 24 x 2) odd days = 124 odd days. = (17 weeks + days) 5 odd days = 5 odd days in 100 years

Odd days in 200 years = (5 x 2) %7 =3 odd days.

Number of odd days in 300 years = (5 x 3) %7 = 1 odd day.

Number of odd days in 400 years = (5 x 4 + 1) %7 = 0 odd day.

Similarly, 800 years, 1200 years, 1600 years, 2000 years has 0 odd days.

Last day of a century cannot be Tuesday or Thursday or Saturday as odd days of any century can be one 0, 1, 3 and 5 days.

For the calendars of two different years to be the same, the conditions to be satisfied are

Both years must be of the same type. i.e., both years must be ordinary years or both years must be leap years.
1st January of both the years must be the same day of the week.

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Profit and Loss – Important Formulas – APSC CSAT Paper Notes

Posted on November 17, 2020March 18, 2023 by admin

Profit and Loss – Important Formulas

Numerical Aptitude Notes for CSAT Paper, SSC and Competitive Exams

Go to Aptitude, Reasoning and Quants Formulas & Notes

Cost Price – The price, at which an article is purchased.

Selling Price – The price, at which an article is sold.

Profit – If S.P. is greater than C.P., the seller is said to have a profit.
Profit = S.P. – C.P.

Loss – If S.P. is less than C.P., the seller is said to have incurred a loss.
Loss = C.P. – S.P.

Loss and Profit are always calculated on Cost Price.

Profit Percentage

Profit % =	Profit x 100 ————– C.P.

Loss Percentage

Loss % =	Loss x 100 ———— C.P.

Selling Price

(100 – Loss %)
SP = —————— x C.P
100

(100 + Gain %)
SP = —————— x C.P
100

Cost Price

100
CP = ——————– x SP
( 100 + Gain %)

100
CP = ——————– x SP
( 100 – Loss %)

Whenever two similar items are sold, one at a gain of L %, and the other at a loss of L %, then the seller always incurs a loss of

Common Loss and Gain %
Loss % = [ ———————————– ] ² = (L/10) ²
10

If a dishonest trader shows as if he sell goods at cost price, but uses false weights, then

Error
Gain % = [ —————————] x 100
(True Value) – (Error)

Simple Interest & Compound Interest – Important Formulas – APSC CSAT Paper Notes

Posted on November 17, 2020March 18, 2023 by admin

Simple Interest (SI) & Compound Interest (CI) – Important Formulas

Numerical Aptitude Notes for CSAT Paper, SSC and Competitive Exams

Go to Aptitude, Reasoning and Quants Formulas & Notes

Principal – The money borrowed or lent out for a certain period is called the principal or the sum.

Interest – Extra money paid for using other’s money is called interest.

Simple Interest (S.I.) – If the interest on a sum borrowed for certain period is reckoned uniformly

Let Principal = P, Rate = R% per annum (p.a.) and Time = T years. Then

Simple Interest =		P x R x T ———–
		100

P =

100 x S.I.
———–

; R =

100 x S.I.
———–

; and T =

100 x S.I.
———–

R x T

P x T

P x R

Compound Interest – the addition of interest to the principal sum of a loan or deposit, or in other words, interest on interest. It is the result of reinvesting interest, rather than paying it out, so that interest in the next period is then earned on the principal sum plus previously accumulated interest.

Let Principal = P, Rate = R% per annum, Time = n

When interest is compound Annually:

Amount = P	(	1 +	R —-	)	n
			100

When interest is compounded Half-yearly:

Amount = P	(	1 +	(R/2) ——	)	2n
			100

When interest is compounded Quarterly:

Amount = P	(	1 +	(R/4) —–	)	4n
			100

When Rates are different for different years, say r₁%, r₂%, r₃% for 1^st, 2^ndand 3^rd year respectively.

Then, Amount = P	(	1 +	r_1 —-	)(		1 +	r_2 —	)(		1 +	r_3 —–	)	.
			100				100				100

Present worth of Rs. P due n years hence is given by:

Present Worth =

P
———————–

(	1 +	r —-	)	ⁿ
		100

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Speed, Time and Distance – Important Formulas – APSC CSAT Paper Notes

Posted on November 17, 2020January 31, 2024 by admin

Speed, Time and Distance – Important Formulas

Numerical Aptitude Notes for CSAT Paper, SSC and Competitive Exams

Go to Aptitude, Reasoning and Quants Formulas & Notes

Basic Formulas

Speed = Distance/Time
Time = Distance/Speed
Distance = (Speed x Time).

Ratio of Speed to Ratio of Time

If the ratio of the speeds of A and B is a: b, then the ratio of the times taken by them to cover the same distance is 1/a: 1/b or b:a

Average Speed Formula

Suppose a car covers a certain distance at a km/hr and an equal distance at b km/hr. The average speed for the whole journey is = 2ab/(a + b) km/hr.

km/hr to m/sec conversion

10 km/hr = 10 x(5/18) m/sec.

m/sec to km/hr conversion

10 m/sec = 10 x(18/5) km/hr.

Important Formulas for Train base Questions

Time taken by a train of length K metres to pass an object be negligible length like a pole or standing man or an electric post is equal to the time taken by the train to cover K metres

Time taken by a train of length K metres to pass a stationery object of length L metres is the time taken by the train to cover (K + L) metres.

Suppose two trains or two objects bodies are moving in the same direction at S m/s and T m/s, where S > T, then their relative speed is = (S – T) m/s.

Suppose two trains or two objects bodies are moving in opposite directions at S m/s and T m/s, then their relative speed is = (S + T) m/s.

If two trains of length K metres and L metres are moving in opposite directions at S m/s and T m/s, then
The time taken by the trains to cross each other = (K + L)/(S + L) sec.

If two trains of length K metres and L metres are moving in same directions at S m/s and T m/s, then
The time taken by the trains to cross each other = (K + L)/(S – L) sec.

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APSC Prelim 2022 CSAT Paper (GS-2) – General Mental Ability sections Questions Analysis

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Geometry and Mensuration Important Formulas

& Properties –

Numerical Aptitude Notes for APSC Prelims CSAT Paper, SSC and Competitive Exams

Circle

Quadrilaterals

Triangle

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Probability – Important Formulas & Notes

Numerical Aptitude Notes for APSC Prelims CSAT Paper, SSC and Competitive Exams

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L.C.M and H.C.F based Questions – Important Formulas

Numerical Aptitude Notes for APSC Prelim CSAT Paper, SSC and Competitive Exams

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Downstream/Upstream Boat Speed – Important Formulas

Numerical Aptitude Notes for APSC Prelim CSAT Paper, SSC and Competitive Exams

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Calendar, Odd days, Leap years – Important Formulas & Notes

Numerical Aptitude Notes for APSC Prelims CSAT Paper, SSC and Competitive Exams

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Profit and Loss – Important Formulas

Numerical Aptitude Notes for CSAT Paper, SSC and Competitive Exams

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Simple Interest (SI) & Compound Interest (CI) – Important Formulas

Numerical Aptitude Notes for CSAT Paper, SSC and Competitive Exams

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Speed, Time and Distance – Important Formulas

Numerical Aptitude Notes for CSAT Paper, SSC and Competitive Exams

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